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"WordPress REST API 主题✅项目合作 二开均可 TG：saolei44✅.YGilyCGMUl" 的搜尋 由 1421 至 1430 約有 1462 筆結果
... Tender Ref.: AFCD/MWFA/2021 Part 1 – Lodging of Tender - 1 - THE GOVERNMENT OF THE HONG KONG SPECIAL ADMINISTRATIVE REGION AGRICULTURE, FISHERIES AND CONSERVATION DEPARTMENT Tender for the Provision of Service of Monitoring Work on Fishing Activities to the Agriculture, Fisheries and Conservation D...
... Tender Ref.: AFCD/MWFA/2020 Part 1 – Lodging of Tender Page 1 of 1 THE GOVERNMENT OF THE HONG KONG SPECIAL ADMINISTRATIVE REGION AGRICULTURE, FISHERIES AND CONSERVATION DEPARTMENT Tender for the Provision of Service of Monitoring Work on Fishing Activities to the Agriculture, Fisheries and Conserva...
[PDF]
SADF0024FR.pdf
... 1 農業持續發展基金 期終報告書 項目名稱：為新一代農民提供互動及可持續的平台(第一階段): 香港農業常見的病蟲 申請機構：香港中文大學________________________________________ 批准日期：2019 年 4 月 10 日_____________________________________ 資助款額：HK$2,512,026_________________________________________ 報告期間：2020 年 1 月 1 日至 2021 年 12 月 31 日_______ 注意 (1) 機構負責人須填妥這份期終報告書，並於項目完...
[PDF]
SADF0024FR.pdf
... 1 農業持續發展基金 期終報告書 項目名稱：為新一代農民提供互動及可持續的平台(第一階段): 香港農業常見的病蟲 申請機構：香港中文大學________________________________________ 批准日期：2019 年 4 月 10 日_____________________________________ 資助款額：HK$2,512,026_________________________________________ 報告期間：2020 年 1 月 1 日至 2021 年 12 月 31 日_______ 注意 (1) 機構負責人須填妥這份期終報告書，並於項目完...
... dry food samples tested in the testing exercise would be 1035/(1035 + 575) x 1805 = 116; and number of dog wet food samples tested would be 575/(1035+575) x 180 = 64. The same principle was applied in determining the number of samples for the rest of the categories. The results of allocation are shown...
... dry food samples tested in the testing exercise would be 1035/(1035 + 575) x 1805 = 116; and number of dog wet food samples tested would be 575/(1035+575) x 180 = 64. The same principle was applied in determining the number of samples for the rest of the categories. The results of allocation are shown...
... dry food samples tested in the testing exercise would be 1035/(1035 + 575) x 1805 = 116; and number of dog wet food samples tested would be 575/(1035+575) x 180 = 64. The same principle was applied in determining the number of samples for the rest of the categories. The results of allocation are shown...
... dry food samples tested in the testing exercise would be 1035/(1035 + 575) x 1805 = 116; and number of dog wet food samples tested would be 575/(1035+575) x 180 = 64. The same principle was applied in determining the number of samples for the rest of the categories. The results of allocation are shown...
... Microsoft Word - AFCD_Launch Service_2022-2023 (AFCD_SET2022)_final.docx Tender Ref.: AFCD/SET2022 Lodging of Tender - - 1 - THE GOVERNMENT OF THE HONG KONG SPECIAL ADMINISTRATIVE REGION AGRICULTURE, FISHERIES AND CONSERVATION DEPARTMENT Tender for the Provision of Launches Services for Operations ...
... Microsoft Word - AFCD_Launch Service_2022-2023 (AFCD_SET2022)_final.docx Tender Ref.: AFCD/SET2022 Lodging of Tender - - 1 - THE GOVERNMENT OF THE HONG KONG SPECIAL ADMINISTRATIVE REGION AGRICULTURE, FISHERIES AND CONSERVATION DEPARTMENT Tender for the Provision of Launches Services for Operations ...